Type your answer here...5x2 - 3x + 10 = 2x2x2 - 6x - 7 = 2x
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
A quadratic equation is any equation that can be expressed as ax2 + bx + c = 0.Note that the a, b and c are specified, x is the only unknown.Example:x2 - 10x - 24 = 0a, b, c are the coefficients of each term.Now x2 appears not to have a coefficient, but remember x2 is the same thing as 1x2 so the coefficient is 1. So a = 1.The second term has a coefficient of -10 because it has a minus, not plus sign in front of it so b = -10.Likewise for c, the third term. C = -24.So you have your terms.There are two popular ways of solving this.You can factorise the equation, or use the Quadratic Formula.I prefer to use the Quadratic Formula, as it is very straightforward, you just need to practise it.The quadratic formula is x = (-b±√(b2-4ac))/2a
Original:i don't think there is an answer. there has to be a number before the x in x2-2x10.by SamanthaActually, there is an answer. It involves using the imaginary number i.To solve:1. Rewrite the equation as x2-2x+10=0.2. This now can be used as a, b, and c for the quadratic formula. (A=1, B=-2, C=10)The quadratic formula is: -b +/- the square root of 4-4(a)(c) ALL divided by 2(a).You then get a negative in the radical which you can convert to an imaginary number using an i.ANOTHER UPDATE:That would be right if she had a mathematic sign before the number 10, but she doesn't. Sorry, man. That's a whooooole different problem.You find that x is something in a+bi form.
5x^2+2x-30=0 x=[-2±√(4+600)]/10 x=(-2±√604)/10 x=(-2±2√151)/10 x=(-1±√151)/5
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Using the quadratic equation formula: x = 1 or x = -10
Unfortunately, the equal sign gets lost in the title. Anyway, you can solve this type of equation using the quadratic formula.
If the equation is 4x squared - 5x + 10 = 0, then you set a = 4, b = -5, c = 10. Replace these numbers in the quadratic formula.
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
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This is a quadratic equation in the form of: 52 - 25x + 30 = 0 Solve by using the quadratic equation formula: x = 2 or x = 3 Or by factorising: (5x-10)(x-3) = 0, which means that x = 10/5 or x = 3
Using proper grammer make question understandable is yes?
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
7r2 = 70r-175 Rearrange the equation and treat it as a quadratic equation: 7r2-70r+175 = 0 Divide all terms by 7: r2-10+25 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (r-5)(r-5) x = 5 and x also = 5 (they both have equal roots)
Solving for any variable in an equation differs from equation to equation. You can use various methods such as the quadratic formula, factoring, brute force algebra etc.ExampleSolve x in the the equation logx8=3/2 Answer(5(root(10)))/4
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