0
It means the same as: 1202pqr
Wiki User
∙ 6y ago
Add your answer:
Earn +20 pts
What is the Product of two Matrices?
The product of a p x q and a r x s matrix is defined only if q = r and, if so, it is a p x s matrix.
What are polynomials that can be factored?
A polynomial can be factored if it has a rational root. If f(x) is a polynomial function of x and if there is a rational number p such that f(p) = 0 then f(x) = (x-p)*g(x) where g(x) is a polynomial whose order is one less than the order of f(x). If p = q/r where q and r are integers, then (x - p) = (x - q/r) = (rx - q)/r which is a rational binomial factor. This does not work if p is irrational which is why p must be rational.
How do you subtract rational numbers with the same or different signs?
Suppose x and y are two rational number.Then x = p/q and y = r/s where p, q, r and s are integers, with q and s being non-zero. Then x - y = p/q - r/s = pq/qs - qr/qs = (pq - rs)/qs. The signs of x and y do not matter, in so far as their signs will be used to determine the signs of p,q, r and s.
What is meant by curl of a vector in maths?
In mathematics, the curl of a vector is the maximum rotation on a vector field, oriented perpendicularly to the certain plane. The curl of a vector is defined by this form: ∇ x F = [i . . . . j . . . . . k] [∂/∂x ∂/∂y ∂/∂z] [P. . . Q. . . .R. . ] ...given that F = <P,Q,R> or Pi + Qj + Rk Perform the cross-product of the terms to obtain: ∇ x F = (∂R/∂y - ∂Q/∂z)i + (∂P/∂z - ∂R/∂x)j + (∂Q/∂x - ∂P/∂y)k
Can a 3 X 4 matrix be multiplied by a 4 X 1 matrix?
Yes. If one matrix is p*q and another is r*s then they can be multiplied if and only if q = r and, in that case, the result is a p*s matrix.
Completely factor the expression 4q2 27r4?
2 x 2 x q x q x 3 x 3 x 3 x r x r x r x r
P and q represents r p q?
tan x
What is the GCF and LCM of the following numbers where p q and r are distinct primes?
The GCF is 1. The LCM is p x q x r.
What is the Product of two Matrices?
The product of a p x q and a r x s matrix is defined only if q = r and, if so, it is a p x s matrix.
How can you factor 11pqr?
11 x p x q x r
What are polynomials that can be factored?
A polynomial can be factored if it has a rational root. If f(x) is a polynomial function of x and if there is a rational number p such that f(p) = 0 then f(x) = (x-p)*g(x) where g(x) is a polynomial whose order is one less than the order of f(x). If p = q/r where q and r are integers, then (x - p) = (x - q/r) = (rx - q)/r which is a rational binomial factor. This does not work if p is irrational which is why p must be rational.
How do you factor this exprission 11pqr?
11 x p x q x r
How are the factors of polynomial P of x related to the roots of polynomial equation P of x equals to 0?
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
How do you round by 195?
Given a number X, divide it by 195 to give a quotient whose integer part is Q and the remainder is R.That is X/195 = Q with remainder R Then if R < 97.5 then the rounded value is 195*Q and if R > 97.5 then the rounded value is 195*(Q + 1).
How do you subtract rational numbers with the same or different signs?
Suppose x and y are two rational number.Then x = p/q and y = r/s where p, q, r and s are integers, with q and s being non-zero. Then x - y = p/q - r/s = pq/qs - qr/qs = (pq - rs)/qs. The signs of x and y do not matter, in so far as their signs will be used to determine the signs of p,q, r and s.
Prove that if a and b are rational numbers then a multiplied by b is a rational number?
If a is rational then there exist integers p and q such that a = p/q where q>0. Similarly, b = r/s for some integers r and s (s>0) Then a*b = p/q * r/s = (p*r)/(q*s) Now, since p, q r and s are integers, p*r and q*s are integers. Also, q and s > 0 means that q*s > 0 Thus a*b can be expressed as x/y where p and r are integers implies that x = p*r is an integer q and s are positive integers implies that y = q*s is a positive integer. That is, a*b is rational.
Factor each expression 11PQR?
11 x P x Q x R = 11PQR
