2x + 4 = 2
2x = -2
x = -1
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
When using substitution the answer to y0.5x plus 2 -y-2x plus 4 is y = -2 (x-1.
4x + 1 = 2x + 5 4x + 1 - 2x = 2x + 5 - 2x 2x + 1 = 5 2x + 1 - 1 = 5 - 1 2x = 4 2x/2 = 4/2 x = 2
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
The value of y in the equation -2x plus 4y -4, is 1 plus x/2.
(4x^3 + 2x^2 + 3x + 4)/(x + 4) = 4x^2 - 14x + 59 - 232/(x + 4)
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
-7
2x + 4 = 16 2x = 16 - 4 2x = 12 x = 12/2 x = 6
-2(5x+3)-2x<-3(2x-4)+2