2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)
(4x + 12)/(8x - 4y) = [4(x) + 4(3)]/(4(2)(x) - 4y] = 4(x + 3)/4(2x - y) = (x+ 3)/(2x - y)
2x-4y = 16 -4y = -2x+16 y = 1/2x-4 Any equation that has a slope of 1/2 but a different intercept of -4.
Get y by itself in standard form y = mx + b where m = slope and b = y intercept 2x + 4y - 10 = 0 4y = -2x +10 y = -2/4 x + 10/4 y = -1/2 x + 2.5 slope = - 1/2
2x - 3y = -4x + 4y = -9from the second equation x = -9-4y , substitute it in the first equation.2(-9-4y)- 3y= -4-18-8y-3y = -4-18-11y = -4-11y = -4+18-11y = 14y = -14/11now, solve for x :x = -9-4yx = -9-4(-14/11)x = -43/11
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
2x - 4y = 8 2x = 4y + 8 x = 2y + 4
This simplifies to 3x-6+4y.
2x + 4y = 72x - 2x + 4y = 7 - 2x4y = -2x + 74y/4 = -2x/4 + 7/4y = -(1/2)x + 7/4Now that y is a function of x, you can give some values for x and find the corresponding values for y. (There are infinitely values for x an y)
(y-2) (x+4)
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
6+(-2x-8)-(-3+12x)-(4y)= 6-2x-8+3-12x-4y=1-14x-4y 1-14x=4y (1-14x)/4=y
2x-4y=-8-2x......-2x-4y=-2x-8(-4y)/-4 | (-2x-8)/-4y=1/2x+2
2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)
(4x + 12)/(8x - 4y) = [4(x) + 4(3)]/(4(2)(x) - 4y] = 4(x + 3)/4(2x - y) = (x+ 3)/(2x - y)
2x-4y=4 -4y=-2x+4 y=1/2x-1 Slope is 1/2 (.5)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)