hujkImproved anwser:2x+6 = 7x-42x-7x = -4-6-5x = -10x = 2
4x = 42x+1Take the logarithm of each side of the equation:x log(4) = (2x+1) log(4)Divide each side of the equation by log(4) :x = 2x + 1Subtract 'x' from each side:x + 1 = 0Subtract ' 1 ' from each side:X = -1Check it out:4x = 42x+14(-1) = (?) 4(-2+1)4(-1) = 4(-1) yay!
(2x + 1)(2x + 1) or (2x + 1)2
2 plus 1-x divided by.
2x + 4 = 2 2x = -2 x = -1
hujkImproved anwser:2x+6 = 7x-42x-7x = -4-6-5x = -10x = 2
4x = 42x+1Take the logarithm of each side of the equation:x log(4) = (2x+1) log(4)Divide each side of the equation by log(4) :x = 2x + 1Subtract 'x' from each side:x + 1 = 0Subtract ' 1 ' from each side:X = -1Check it out:4x = 42x+14(-1) = (?) 4(-2+1)4(-1) = 4(-1) yay!
(2x + 1)(2x + 1) or (2x + 1)2
2 plus 1-x divided by.
2x + 4 = 162x + 4 - 4 = 16 - 42x = 122x/2 = 12/2x = 6
The solution to the equation 2x plus 2 is 2(x + 1).
2x + 4 = 2 2x = -2 x = -1
(2x + 1)(x + 2)
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
(2x + 3)(x + 1 ) = 2x^2 +5x +3
42x + 1 = 8x - 1Subtract 1 from each side:42x = 8x - 2Subtract 8x from each side:34x = -2Divide each side by 34:x = -2/34 = -1/17
2x + 3 > 72x + 3 - 3 > 7 - 32x > 42x/2 > 4/2x > 2The solution is all real numbers greater than 2.