xy plus 2x plus 4y plus 8 or
(xy+2x) + (4y+8) or
x(y+2) + 4(y+2) or
(x+4)(y+2)
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
(x-y) + (xy - 1) = (x - 1)(y + 1)
That equals 2xy + 3y which factors to y(2x + 3)
xy + xy = 2xy
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
(x + 4)(y - 2)
(x + 4)(y - 2)
(x + 4)(y - 2)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
(y-2) (x+4)
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
(x - 1)(2x + y)
4
Divide by 'x'; x2+xy/x = x(x+y)
If this is a question about factorisation check the signs. As it stands, it cannot be factorised.
xy(3x - 2y)(2x + 3y)
In order to combine terms, the variable(s) must be the same and the exponent(s) must be the same on the variables. Since you have an x2 term, x term, xy term and y term, none of the terms can be combined. So, the answer is: x2 + 4x + xy + 4y. The only thing you could do in this problem is to factor out a 4 from the 4x & 4y so another way to write this is: x2 + xy + 4(x + y).