xy plus 2x plus 4y plus 8 or
(xy+2x) + (4y+8) or
x(y+2) + 4(y+2) or
(x+4)(y+2)
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2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
(x-y) + (xy - 1) = (x - 1)(y + 1)
That equals 2xy + 3y which factors to y(2x + 3)
xy + xy = 2xy
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)