I would not even attempt to factor this, so the quadratic formula.
X = - b (+/-) sqrt(b2 - 4ac)/2a
a = 3
b = - 6
c = - 7
X = - (- 6 ) (+/-) sqrt[(- 6)2 - 4(3)(- 7)]/2(3)
X = 6 (+/-) sqrt(36 + 84)/6
X = 6 (+/-) sqrt(120)/6
X = 6 (+/-) sqrt( 22 * 30)/6
X = [6 (+/-) 2sqrt(30)]/6
----------------------------------------exact answer less clean up
It is, as stated, 2x2 + x - 1 = 0. That is the quadratic form.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
It is the general form of a quadratic equation.
No
Linear.
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
A quadratic of the form ax2 + bx + c has no maximum if a > 0: it gets infinitely large. If a = 0 then it is not a quadratic. If a < 0 then the quadratic does have a maximum, and it is -D/4a where D is the discriminant = b2 - 4ac
y=±√15
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
The standard form of a quadratic equation is ( ax^2 + bx + c = 0 ), where (a), (b), and (c) are constants and (a \neq 0).
It is, as stated, x2 - 5x + 25/4 = 0
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,