7(y+2) is equivalent to 7y+14
a + 7y
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
y^2 + 7y + 12 = (y+4)(y+3)
7y+5=-9... 7y must equal -14 therefore y must be -2
16+7y-8 = 7y+16-8 = 7y+8
(y + 5) (y + 2)
(4y - 1)(y + 2)
-7y + 4y = -3y
1 + 7y = 5x - 2 7y = 5x - 3 - 5x = - 7y - 3 x = 7/5y + 3/5 ---------------------
x+7y=16 ---------------------------1 3x- 7y=4 ---------------------------2 ------------------------------------------------------------------------------------------------------------------ 1+2 x+7y=16 3x-7y=4 4x=20 x=5 substitute x = 5 in x+7y=16 (5)+7y=16 7y=11 y=11/7
If the equations are 8x + 7y = 37, and 2y = 4x -2 then the answer is yes.
If you mean: 3y^2-7y+3-5y+3-4y^2 then it is simplified to -y^2-12y+6