Step 1: 3(7y2 + 24y - 16) Step 2: 3(7y - 4)(y + 4) Assuming original expression was equal to zero, y = 4/7 or -4
(7y - 5)(y + 1)
That factors to y(y2 + 7y - 5)
Zero. There is no term with just y in it.
By following the directions in your textbook. Or you could try paying attention in class; that would probably work too.
Step 1: 3(7y2 + 24y - 16) Step 2: 3(7y - 4)(y + 4) Assuming original expression was equal to zero, y = 4/7 or -4
(7y - 5)(y + 1)
That factors to y(y2 + 7y - 5)
Just use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + CJust use the power rule for each part, and add or substract. The answer is y + 7y2/2 - y3/3 + C
Zero. There is no term with just y in it.
Yx7y = 7y2 (squared )
By following the directions in your textbook. Or you could try paying attention in class; that would probably work too.
You can factor this multivariate polynomial (a polynomial with several variables, here x and y), by looking at it as a univariate polynomial in either x or y. This would give you a simple second order equation of the form ax2+bx+c, which you can solve. This will give you 2 solutions, say x1 and x2, and can then factor your polynomial to a(x-x1)(x-x2). In our case: a=8, b=-y and c=-7y2 and the solutions for this equation are x1=y and x2=-7/8*y and this gives us 8x2 - xy -7y2 = 8(x-y)(x+7/8y) = (x-y)(8x+7y)
Since 98y9 is a multiple of 14y2, it is automatically the LCM of this problem.
When factoring an expression we are attempting to find two or more numbers or expressions that when multiplied will result in our starting expression. For example, to factor 12 we would say 2*2*3 because when multiplied, it would equal 12. To factor this expression, start by grouping both sides with parentheses. 4x^2-4x+2xy-2y (4x^2-4x) + (2xy-2y) Now use reverse distribution to pull a 4x out of the first part and a 2y out of the second. (4x^2-4x) + (2xy-2y) 4x(x-1) + 2y(x-1) looking at the expression as a whole we see that both terms have a factor of x-1. So, we reverse distribute again to get a factored expression 4x(x-1) + 2y(x-1) (x-1)(4x+2y) Factor out a two from the second expression to get the final, fully factored answer. (x-1)(4x+2y) 2(x-1)(2x+y)
You cannot solve it since only one side of an equation is given. If the equation was y4 + 5y2 - 84 = 0 then y4 + 12y2 - 7y2 - 84 = 0 or y2*(y2 + 12) - 7*(y2 + 12) = 0 or (y2 - 7)*(y2 + 12) = 0 then y2 = 7 or y2 = - 12 y = +or- sqrt(7) and, if you are in the complex domain, also y = +or- i*sqrt(12) where i is the imaginary square root of -1.
-- make a list of 20 or 30 small numbers-- one at a time, put each number in place of 'y', and figure out what 'x' is-- mark a point at the pair of numbers you have for (x, y) on the graph-- after a while, you'll start to see the graph take shape, and you can fill in the gaps between the points