2 FeCl2 + Cl2 --> 2 FeCl3
Chlorine, a strong oxidizer, oxidizes Iron (II) valency to Iron (III).
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
The reaction will proceed to the right. 2 PCl3 will be consumed.
2K + Cl2 --> 2KCl
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
3 MgCl2 + N2 = Mg3N2 + 3 Cl2
Since Fe is a transition metal, the equation varies. If Fe has the oxidation state of +2: Fe + Cl2 -> FeCl2 If Fe has the oxidation state of +3: 2 Fe + 3 Cl2 -> 2 FeCl3
The chemical symbol for iron is Fe, and the symbol for chlorine is Cl. If you meant when they are combined, there are two possibilities: FeCl2 for ferrous chloride or FeCl3 for ferric chloride.
Ferric or Iron (III) = Fe3+Chloride = Cl-Fe3+ + Cl- = Fe2Cl
Cl2 + H2O = HOCl + HCl
Fe + O2 ==> Fe2O3 need a 4 in front of Fe and a 3 in front of O2, as in the following:4Fe + 3O2 ===> 2Fe2O3
The Cl- ions in HCl is oxidized to Cl2
This equation is 2 Fe + 3 Cl2 -> 2 FeCl3.
It is not possible.
Any reaction occur.
3(Cl2) + 3(H2O) = 5(HCl) + 1(HClO3)
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
CuCl2 is the product.