Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
The reaction will proceed to the right. 2 PCl3 will be consumed.
2K + Cl2 --> 2KCl
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
3 MgCl2 + N2 = Mg3N2 + 3 Cl2
When iron (Fe) reacts with chlorine gas (Cl2), they form iron (III) chloride (FeCl3) according to the equation: 2 Fe + 3 Cl2 → 2 FeCl3. This reaction is a redox reaction where iron is oxidized and chlorine is reduced.
The chemical symbol for iron is Fe, and the symbol for chlorine is Cl. If you meant when they are combined, there are two possibilities: FeCl2 for ferrous chloride or FeCl3 for ferric chloride.
The balanced equation for the reaction between iron and chlorine gas is: 2 Fe + 3 Cl2 → 2 FeCl3.
Fe + O2 ==> Fe2O3 need a 4 in front of Fe and a 3 in front of O2, as in the following:4Fe + 3O2 ===> 2Fe2O3
The balanced equation for iron reacting with chlorine to form iron(III) chloride is: 2 Fe(s) + 3 Cl2(g) → 2 FeCl3(s)
Ferric chloride can be reduced to ferrous chloride by adding a reducing agent such as hydrochloric acid or sulfur dioxide. The reaction involves the transfer of electrons from the reducing agent to the ferric ion, converting it to the ferrous ion. This reaction can be represented as: FeCl3 + HCl -> FeCl2 + HCl + Cl2.
Any reaction occur.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
The equation for the reaction of iron with chlorine to form ferric chloride is: Fe + 3Cl2 -> 2FeCl3. For ferrous chloride: Fe + 2Cl2 -> 2FeCl2.
Cl2 + 2KI → 2KCl + I2
No, the reaction F2 + NaCl does not produce NaF + Cl2. When F2 reacts with NaCl, it forms NaF and Cl2 gas, not NaF + Cl2.