2 FeCl2 + Cl2 --> 2 FeCl3
Chlorine, a strong oxidizer, oxidizes Iron (II) valency to Iron (III).
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
The reaction will proceed to the right. 2 PCl3 will be consumed.
2K + Cl2 --> 2KCl
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
3 MgCl2 + N2 = Mg3N2 + 3 Cl2
When iron (Fe) reacts with chlorine gas (Cl2), they form iron (III) chloride (FeCl3) according to the equation: 2 Fe + 3 Cl2 → 2 FeCl3. This reaction is a redox reaction where iron is oxidized and chlorine is reduced.
The chemical symbol for iron is Fe, and the symbol for chlorine is Cl. If you meant when they are combined, there are two possibilities: FeCl2 for ferrous chloride or FeCl3 for ferric chloride.
2Fe + 3Cl2 ---> 2FeCl3 (iron(III) chloride) Fe +Cl2 -> FeCl2 (iron(II) chloride)
Fe + O2 ==> Fe2O3 need a 4 in front of Fe and a 3 in front of O2, as in the following:4Fe + 3O2 ===> 2Fe2O3
This equation is 2 Fe + 3 Cl2 -> 2 FeCl3.
Ferric chloride can be reduced to ferrous chloride by adding a reducing agent such as hydrochloric acid or sulfur dioxide. The reaction involves the transfer of electrons from the reducing agent to the ferric ion, converting it to the ferrous ion. This reaction can be represented as: FeCl3 + HCl -> FeCl2 + HCl + Cl2.
Any reaction occur.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
2KI + Cl2 = 2KCl + I2
Ferric or Iron (III) = Fe3+Chloride = Cl-Fe3+ + Cl- = Fe2Cl
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.