mx2 = 2m
(m-2)/(m+2) * m/(m-1) = [(m-2)*m]/[(m+2)*(m-1)] = (m2 - 2m)/m2 + m - 2)
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
1
m7/2
the area of an mxm square is m^2. For example, a 3x3 square has area 3^2 or 9
if by m2 you mean m multiplied by 2, then m= 2 2/3if by m2 you mean m squared, then m still =2 2/3, because the m squared becomes m times m which equals 2m
85*2+m
Area of a possible rectangle: 9 times 2 = 18 square m
2
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7