44m
7 x 19 cm
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
Let the width be x-12 and the length be x: 2(x-12+x) = 52 2x-24+2x = 52 2x+2x = 52+24 4x = 76 Divide both sides by 4 to determine the value of x: x = 19 Therefore: width = 7 cm and the length = 19 cm
44m
The length of the rectangle is 27 meters and the width is 19 meters.
If we're talking a rectangle here, all you need to do is add length and width then double your answer...
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
2x+2y=86 y=19 2x+2(19)=86 2x=48 x=24 length=19 (given in question) width= 24 (solved above)
7 x 19 cm
If the length of a rectangle is 33, and the width is 19, the perimeter would be 104. === === P = 2 (l+w) P = 2 (33+19) P = 2 (52) P = 104
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
The width is 228/12 = 19 feet
Let the width be x-12 and the length be x: 2(x-12+x) = 52 2x-24+2x = 52 2x+2x = 52+24 4x = 76 Divide both sides by 4 to determine the value of x: x = 19 Therefore: width = 7 cm and the length = 19 cm
The area of rectangle is : 152.0