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Let x equal the lowest number of the three.

Therefore:

x + x + 1 + x + 2 = 228

3x + 3 = 228

3x = 228 - 3

3x = 225

x = 75

Thus the 3 numbers are 75, 76 & 77.

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Q: What is the answer to the question what are the numbers if the sum of three consecutive numbers is 228?
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Related questions

What are three consecutive numbers of 681?

The numbers are 226, 227 and 228.


The sum of three consecutive even integers is 228 find the integers?

The three numbers added together will equal 228. The average of the three numbers will be 228 / 3 = 76. If you take one even integer from either side of 76, you get 74 and 78.Therefore, the three consecutive even integers which equal 228 are 74, 76 and 78.


What are the three consecutive integers that have a sum of 228?

They are: 75+76+77 = 228


The sum of three consecutive natural numbers is 681 find the numbers?

The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.


The sum of three consecutive multiples of 6 is 666find the multiples?

The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.


The sum of three consecutive odd intrgers is 228 what are the inetgers?

This has no answer. The sum of three odd integers is always odd.


If sum of two consecutive integers is 228 find the integers?

The sum of any two consecutive integers must be an odd number. So this question is incorrect.


The sum of two consecutive integers is 228 what are the numbers?

This would be impossible as, seeing as one of the integers would be odd, the result would be an odd number.


What are four consecutive numbers that add up to 234?

Let "a" be the first of the four numbers. Then we are told:a + (a + 1) + (a + 2) + (a + 3) = 234∴ 4a + 6 = 234∴ 4a = 228∴ a = 57So the numbers are 57, 58, 59 and 60


Two numbers have a sum of 31 and a product of 228 What are the numbers?

If two numbers have a sum of 31 and a product of 228, then the two numbers are 12 and 19. Adding them will give you 31, and multiplying them gives you 228.


The sum three consecutive multiples of 6 is 666 find these multiples?

Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228


The sum of three consecutive integers is 228 What are the integers?

Let the first one be x, the second be x + 1, and the third one is x + 2. So we have,x + x+1 + x +2 = 2283x + 3 = 228 subtract 3 to both sides3x = 225 divide by 3 to both sidesx = 75x + 1 = 75 + 1 = 76x + 2 = 75 + 2 = 77Thus, the three consecutive integers are 75, 76, and 77.