b2+11b-42 = (b+14)(b-3) when factored
(-8 + b2) - (5 + b2) = -8 + b2 - 5 - b2 = -13
24a + b2 + 3a + 2b2= 27a + 3b2
a2+2a2b+2ab2+b2
The equation (b2 - 2b) + (3b - 6) = b2 + b - 6
The polynomial IS b2 - 6b + 8.
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
a2
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
The equation A H b1 plus b2 times 2 equals 8. This is a math problem.
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
l a2 b2 is c2!!Its completely norma
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z