Q: What is 24a plus b2 plus 3a plus 2b2?

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We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.

b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.

The standard equation for an ellipse centered at the origin is [x2/a2] + [y2/b2] = 1 We also have the relationship, b2 = a2 - c2 where c is the distance of the foci from the centre and a & b are the half lengths of the major and minor axes respectively. When the length of the minor axis equals the distance between the two foci then 2b = 2c : b = c. Thus, a2 =b2 + c2 = 2b2 One of the formulae for the eccentricity of an ellipse is, e = √[(a2 - b2)/a2] Thus, e = √[(2b2 - b2) / 2b2] = √½ = 1/√2.

ab=50 a/b=2 a=2b 2b2=50 b2=25 b=5 5a=50 a=10 (10,5)

You can start by using the formula for the difference of two squares. Actually, after that I don't think you can factor it any further.

Related questions

We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.

b2 + b2 = 2b2 (when terms are alike, just add them up)

2b2 + 8 para b = -3

b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.

a(b+3)+b(b+3)

This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)

(3a + b)(3a - b)

Assuming the exponential form, 9a4 - b2 has the factors (3a + b)(3a - b).

b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)Check:(b - 2)(b2 - 3b - 6)= b(b2 - 3b - 6) - 2(b2 - 3b - 6)= b3 - 3b2 - 6b - 2b2 + 6b + 12= b3 - 5b2 + 12

There is a formula for the "difference of squares." In this case, the answer is (3A + B)(3A - B)

The standard equation for an ellipse centered at the origin is [x2/a2] + [y2/b2] = 1 We also have the relationship, b2 = a2 - c2 where c is the distance of the foci from the centre and a & b are the half lengths of the major and minor axes respectively. When the length of the minor axis equals the distance between the two foci then 2b = 2c : b = c. Thus, a2 =b2 + c2 = 2b2 One of the formulae for the eccentricity of an ellipse is, e = √[(a2 - b2)/a2] Thus, e = √[(2b2 - b2) / 2b2] = √½ = 1/√2.

(-8 + b2) - (5 + b2) = -8 + b2 - 5 - b2 = -13