Approximately 17 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
The length of the other diagonal works out as 12cm
The diagonal length is about 18.44 inches.
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
The diagonal length = 7.07 inches.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter of this square is 56.569 meters.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
The diagonal is 14 inches.