Approximately 10 inches.
Approximately 17 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
The diagonal length is about 18.44 inches.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
Approximately 17 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
The length of the other diagonal works out as 12cm
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
The diagonal length is about 18.44 inches.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
The diagonal length = 7.07 inches.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The perimeter of this square is 56.569 meters.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.