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Assuming this question is asking about a rectangle:
Perimeter = 2l + 2w and according to this problem Perimeter = 96, so
96 = 2l + 2w
If l = 5w, then we can replace each l in the statement above with 5w, so
96 = 2(5w) + 2w
96 = 10w + 2w
96 = 12w
8 = w
If 8 = w, and l = 5w, then l = 5 times 8 = 40
The area of a rectangle is length (l) times width (w), so
A = lw
A = (40) (8)
A = 320 square units
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What is the area of 48 96?
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What is the area and perimeter of the rectangle 3 ft wide 45 ft long?
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If the area of a square is 576 square feet what is the perimeter?
96 feet.
What is the area of 48 96?
48 times 96 equals 4,608.
What are the dimensions of a rectangle that has a perimeter of 56 units and 96 square units?
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The perimeter of the triangle is 48centimeters what is the perimeter of the square?
The perimeter of the square is 96.
What are the dimensions of a reactangle that has a perimeter of 56 units and an area of 96 square units?
4 x 24
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units?
4 x 24
What is the length and width of a room with an area of 96 square feet and a perimeter of 40 feet?
8 by 12
What is the area of a rectangle if the perimeter of the rectangle is 96 cm?
Any number less than 576 cm2. A square, with sides of 24 cm will have a perimeter of 96 cm and an area of 576 cm2. Suppose the sides of the rectangle are 24+x cm and 24-x cm, where 0<x<24. Then the perimeter will be 96 cm while the area will be (24+x)*(24-x) = 576 - x2 cm2 The area can have any value in the range (0, 576) depending on the value of x.
What is the area and perimeter of the rectangle 3 ft wide 45 ft long?
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What is the area of a regular hexagon with the given measurement of 48-inch perimeter?
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What is the maximum perimeter of the rectangle 96?
Assuming 96 refers to the area of therectangle, the answer is: infinite. Consider the following sequence of rectangles with breadh B units and length L units.: Breadth = 1 Length = 96. Area = 96, Perimeter = 194 B= 0.1, L = 960. A = 96, P = 1920.2 B = 0.01, L =9600. A = 96, P = 19200.02 B = 0.001, L = 96000. A = 96, P = 192000.002 There is no limit to how small B can get and therefore, how large P can get.
