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If 6 is the side of a regular pentagon, the area is 61.937
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Area of a regular pentagon with a radius of 3 cm?
21.4
Find the perimeter and area of a pentagon with side length 8 cm?
Area = 110.11 cm2
What is the area of a regular pentagon if the radius r of the circumcircle is 3.4 cm and half the side length a is 2 cm rounded to 1 decimal place?
In a regular pentagon there are 5 vertices which connect to the circumcentre each a distance r = 3.4 cm away. This creates 5 triangles inside the pentagon; so the area of the pentagon is the sum of these five triangles; as the pentagon is regular, this is the same as 5 times the area of one of these triangles. The length of each side of the pentagon is twice half the length of one side → side = 2 × a = 2 × 2 cm Consider one side and the two radii connecting its ends to the circumcentre; this is an isosceles triangle, so dropping a perpendicular from the circumcentre to the side of the pentagon bisects the base of the triangle (side of the pentagon). From this the height of the triangle can be calculated using Pythagoras: half_side² + height² = radius² → (a cm)² + height² = (r cm)² →(2 cm)² + height² = (3.4 cm)² → height² = (3.4 cm)² - (2 cm)² → height = √(3.4² - 2²) cm area_pentagon = 5 × area_triangle = 5 × ½ × base × height = 5 × ½ × (2 × 2 cm) × √(3.4² - 2²) cm = 10 × √7.56 cm² = 27.495... cm² ≈ 27.5 cm² to 1 dp
What is the surface area of a regular pentagon that has a perimeter of 37.5 cm?
The 5 sided regular pentagon will consist of 5 congruent isosceles angles with equal sides of 6.379881063 cm by using the sine rule and 2 equal base angles of 54 degrees with an apex angle of 72 degrees opposite side 7.5 cm Area of the pentagon: 0.5*6.379881063^2 *sin(72)*5 = 96.77685379 square cm
What is the area of a triangle with a base of 6 cm and a height of 9 cm?
17 cmImproved Answer:-Area = 1/2*6*9 = 27 square cm
If S equals 6 Cm and R equals 5.1 Cm find the area of the regular pentagon round the answer to one decimal place?
61.90(:
Area of a regular pentagon with a radius of 3 cm?
21.4
The shapes on a soccer ball include a regular pentagon with an apothem of 3.5 cm. What is the area of the regular pentagon Round to the nearest whole number?
45 cm
If a equals 2 cm and r equals 3 cm find the area of the regular pentagon?
27.50 (:
Find the perimeter and area of a pentagon with side length 8 cm?
Area = 110.11 cm2
How do you find perimeter of pentagon with side 6 cm?
It's got 5 sides, so multiply 6 cm by 5...
When the side length of a regular pentagon is increased its perimeter increases by 12.5 cm how much longer is the new side length?
2.5 cm. If the area of a pentagon is increased by 12.5 cm and each side of the pentagon is the same length, then each side would increase by 2.5 cm. (12.5 cm/ 5 sides = 2.5 cm/ side.
A circle is inscribed in a regular pentagon whose sides are 12 cm. Find the area inside the pentagon and outside the circle?
124
If a 2 cm and r 3.4 cm find the area of the regular pentagon Round the answer to one decimal place?
27.50
What is the perimeter of a regular pentagon with a side length of 7.2 cm?
we know that regular pentagon has 5 equilateral triangle . now ,perimeter of pentagon = 5 Xside . now,perimeter of a regular pentagon with a side length of 7.2 cm . perimeter = 7.2 X 5 =36 cm .
What is the area of a regular pentagon if the radius r of the circumcircle is 3.4 cm and half the side length a is 2 cm rounded to 1 decimal place?
In a regular pentagon there are 5 vertices which connect to the circumcentre each a distance r = 3.4 cm away. This creates 5 triangles inside the pentagon; so the area of the pentagon is the sum of these five triangles; as the pentagon is regular, this is the same as 5 times the area of one of these triangles. The length of each side of the pentagon is twice half the length of one side → side = 2 × a = 2 × 2 cm Consider one side and the two radii connecting its ends to the circumcentre; this is an isosceles triangle, so dropping a perpendicular from the circumcentre to the side of the pentagon bisects the base of the triangle (side of the pentagon). From this the height of the triangle can be calculated using Pythagoras: half_side² + height² = radius² → (a cm)² + height² = (r cm)² →(2 cm)² + height² = (3.4 cm)² → height² = (3.4 cm)² - (2 cm)² → height = √(3.4² - 2²) cm area_pentagon = 5 × area_triangle = 5 × ½ × base × height = 5 × ½ × (2 × 2 cm) × √(3.4² - 2²) cm = 10 × √7.56 cm² = 27.495... cm² ≈ 27.5 cm² to 1 dp
What is the perimeter of a regular pentagon with a length of 17 cm?
A pentagon has 5 sides A regular pentagon has all sides equal → perimeter of regular pentagon with side 17 cm = 5 × 17 cm = 85 cm
