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What is the area of a 6 cm pentagon?
If 6 is the side of a regular pentagon, the area is 61.937
What is the area of a regular pentagon if the radius r of the circumcircle is 3.4 cm and half the side length a is 2 cm rounded to 1 decimal place?
In a regular pentagon there are 5 vertices which connect to the circumcentre each a distance r = 3.4 cm away. This creates 5 triangles inside the pentagon; so the area of the pentagon is the sum of these five triangles; as the pentagon is regular, this is the same as 5 times the area of one of these triangles. The length of each side of the pentagon is twice half the length of one side → side = 2 × a = 2 × 2 cm Consider one side and the two radii connecting its ends to the circumcentre; this is an isosceles triangle, so dropping a perpendicular from the circumcentre to the side of the pentagon bisects the base of the triangle (side of the pentagon). From this the height of the triangle can be calculated using Pythagoras: half_side² + height² = radius² → (a cm)² + height² = (r cm)² →(2 cm)² + height² = (3.4 cm)² → height² = (3.4 cm)² - (2 cm)² → height = √(3.4² - 2²) cm area_pentagon = 5 × area_triangle = 5 × ½ × base × height = 5 × ½ × (2 × 2 cm) × √(3.4² - 2²) cm = 10 × √7.56 cm² = 27.495... cm² ≈ 27.5 cm² to 1 dp
Can a regular pentagon with a side measuring 5 cm be congruent to another regular pentagon with a of perimeter 25cm?
Yes because 5*5 = 25 cm
What is the surface area of a regular pentagon that has a perimeter of 37.5 cm?
The 5 sided regular pentagon will consist of 5 congruent isosceles angles with equal sides of 6.379881063 cm by using the sine rule and 2 equal base angles of 54 degrees with an apex angle of 72 degrees opposite side 7.5 cm Area of the pentagon: 0.5*6.379881063^2 *sin(72)*5 = 96.77685379 square cm
What is the perimeter of a regular pentagon with a side length of and radic50?
The perimeter of a regular pentagon is five times the side length.
What is the area of a 6 cm pentagon?
If 6 is the side of a regular pentagon, the area is 61.937
The shapes on a soccer ball include a regular pentagon with an apothem of 3.5 cm. What is the area of the regular pentagon Round to the nearest whole number?
45 cm
What is the perimeter of a regular pentagon with a length of 17 cm?
A pentagon has 5 sides A regular pentagon has all sides equal → perimeter of regular pentagon with side 17 cm = 5 × 17 cm = 85 cm
If a equals 2 cm and r equals 3 cm find the area of the regular pentagon?
27.50 (:
What is the area of a regular pentagon if the radius r of the circumcircle is 3.4 cm and half the side length a is 2 cm rounded to 1 decimal place?
In a regular pentagon there are 5 vertices which connect to the circumcentre each a distance r = 3.4 cm away. This creates 5 triangles inside the pentagon; so the area of the pentagon is the sum of these five triangles; as the pentagon is regular, this is the same as 5 times the area of one of these triangles. The length of each side of the pentagon is twice half the length of one side → side = 2 × a = 2 × 2 cm Consider one side and the two radii connecting its ends to the circumcentre; this is an isosceles triangle, so dropping a perpendicular from the circumcentre to the side of the pentagon bisects the base of the triangle (side of the pentagon). From this the height of the triangle can be calculated using Pythagoras: half_side² + height² = radius² → (a cm)² + height² = (r cm)² →(2 cm)² + height² = (3.4 cm)² → height² = (3.4 cm)² - (2 cm)² → height = √(3.4² - 2²) cm area_pentagon = 5 × area_triangle = 5 × ½ × base × height = 5 × ½ × (2 × 2 cm) × √(3.4² - 2²) cm = 10 × √7.56 cm² = 27.495... cm² ≈ 27.5 cm² to 1 dp
A circle is inscribed in a regular pentagon whose sides are 12 cm. Find the area inside the pentagon and outside the circle?
124
If a 2 cm and r 3.4 cm find the area of the regular pentagon Round the answer to one decimal place?
27.50
What is the area of a regular pentagon that has a perimeter of 50cm?
Using trigonometry and the sine rule the area of the regular 5 sided pentagon with a perimeter of 50cm works out as 172.048 square cm rounded to 3 decimal places.
What is the perimeter of a regular pentagon with a side of 8 cm?
A pentagon has 5 sides. In a regular pentagon, all 5 sides are equal length, so the perimeter = 5 x 8 cm = 40 cm
What is the perimeter of a regular pentagon with a side length of 13 cm?
A regular pentagon is equilateral(all sides are equal) 5*13 = 65 cm
Can a regular pentagon with a side measuring 5 cm be congruent to another regular pentagon with a of perimeter 25cm?
Yes because 5*5 = 25 cm
If S equals 6 Cm and R equals 5.1 Cm find the area of the regular pentagon round the answer to one decimal place?
61.90(:
