The 5 sided regular pentagon will consist of 5 congruent isosceles angles with equal sides of 6.379881063 cm by using the sine rule and 2 equal base angles of 54 degrees with an apex angle of 72 degrees opposite side 7.5 cm
Area of the pentagon: 0.5*6.379881063^2 *sin(72)*5 = 96.77685379 square cm
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
The boy had to find the area and perimeter of the pentagon.
There can be no such formula in general. A formula will exist if the area is a regular polygon (or a circle).
About 387 m^2 1.72*s^2 s=perimeter/5 s=75/5=15 1.72*15*15=387
Area = 1,918,570 ft2
Using trigonometry and the sine rule the area of the regular 5 sided pentagon with a perimeter of 50cm works out as 172.048 square cm rounded to 3 decimal places.
The formula is 1/2 (apothem) (perimeter)
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
The perimeter of the pentagon would be 18 x 5 = 90 centimetres. The area of the pentagon, rounded to two decimal places, would be (5 x 182 x tan(54))/4 = 272.89 cm2.
The boy had to find the area and perimeter of the pentagon.
Area = 139.36 ft2
add all of the triangle area in a pentagon to get areaThe area A of a regular polygon with n sides each s units long, perimeter p, and apothem a:A = (ans)/2 or A = (ap)/2.
There can be no such formula in general. A formula will exist if the area is a regular polygon (or a circle).
About 387 m^2 1.72*s^2 s=perimeter/5 s=75/5=15 1.72*15*15=387
The area of a regular hexagon with a perimeter 120m is about 1039.2m2
Area = 1,548.43 ft2
Area = 1,918,570 ft2