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Q: What is the area of a hexagon with a side length of fourteen feet?

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The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.

36 feet

196 square feet. To calculate square feet simply multiply length by width - the result is the area in square feet.

there are an infinite number of triangles that have fourteen square feet

Assuming this is a regular hexagon, with all sides and all angles the same.The area of a regular hexagon of side length is given byA = 3 * (square root of 3) / 2 * t squared, where t = side. This is approximately equal to 2.598076211 * t2With t = 9 feet, the Area = 2.598076211 * 9 * 9 = 210.444173square feet

2744 cubic feet

About 10.39 square feet.The formula is A = 3/2 (sqrt 3) s2(this is about 2.598 times the side length squared)

Three feet.

Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet

Area is length times width. If the length and width are measured in feet, the area will be in square feet.

Its length is 10 feet.

area = length x width width = area/length 16/8 = 2 feet

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