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Q: What is the area of a lot with the dimensions 125.46x57.57x130.00 feet?

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You have to multiply the two dimensions to get the area. In this case the answer will be 7,500 square feet.

The dimensions of a square with an area of five acres are:Side lengths of 466.7 feetPerimeter of 1,867 feetDiagonal measurement of 660 feetAn area of 217,800 square feet

The dimensions of the rectangular lot are: 30m by 15m

It depends on the shape of the area. If the shape is a square, each side would measure about 120 feet.

6,000 Sq. Ft.

about 5000 square feet, if the corners are roughly square.

This question cannot be answered sensibly. An acre is a measure of area, with dimensions [L2]. A foot is a measure of distance, with dimensions [L]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.

An acre contains 43,560 square feet. The actual dimensions of the lot can vary, perfectly square would be just under 209 by 209 feet.

The area doesn't tell you the dimensions. It doesn't even tell you the shape. If the lot happens to be a rectangle, then its length and width can be anything you want, just as long as when you multiply them, their product is 16,117.

Area = length * width 235.3 feet * 102.5 feet = 24118.25 square feet

An acre is 43,560 square feet. You'll have to do some math to decide what proportions you want that one acre lot to take.

For a square-shaped lot, each of the four sides would be about 2,333.45 feet long.

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