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The area of rectangle is : 32.0
Kaela Mosciski
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The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cm what is the area of the rectangle?
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
Is the area the same on all rectangles with the same perimeter?
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
What is the area of a rectangle with a length of 12 and width of 8?
96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.
The length of a rectangle is 3 meters greater than the width The area is 88 meters 2 what are the dimensions of rectangle?
Come on! 88 = 11 x 8, end of story.
What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
What is the area of a rectangle that is 4cm long and 2cm wide?
It is: 4*2 = 8 square cm
The length of a rectangle is 4cm longer than the width if the perimeter of the rectangle is 20cm what is the area of the rectangle?
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
A rectangle is 4cm longer than it is wide what are the demesions if the area is 8cm?
Area of a rectangle = length x width If length = L and width = W, then Area = L x W For this case, the length is 4 cm longer than the width. Therefore, L = W + 4cm Replace length in the area equation at the top with this new L value: Area = (W + 4cm) x W Area = W^2 + (4cm) x W And area is 8 cm^2 (I assume you meant to say 8cm^2 is the area) Then: 8cm^2 = W^2 +4W This is a quadratic equation (because of the w^2 value), if you solve for W using the quadratic formula (Google it), you get W = 1.464cm Therefore, the length L = W + 4cm = 1.464cm + 4cm = 5.464cm Dimensions are L = 5.464cm and W = 1.464cm
What is the perimeter of a 4cm by 2cm rectangle?
12cm
There area of the rectangle is 128. If the width is twice the length what is the length?
The dimensions are 16 units by 8 units of mearsurement
What is the total area of the rectangle 8ft 10ft 2ft 2ft?
The dimensions given are not that of a rectangle but are probably that of an isosceles trapezoid in which case it is:- Area = 0.5*(8+10)*2 = 18 square feet
Is the area the same on all rectangles with the same perimeter?
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
What is the area of a rectangle with a length of 12 and width of 8?
96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.
The length of a rectangle is 3 meters greater than the width The area is 88 meters 2 what are the dimensions of rectangle?
Come on! 88 = 11 x 8, end of story.
What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
The length of a rectangle is 8 cm more than the width find the dimensions of the rectangle if the area is 153 cm square?
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
What is the perimeter of a rectangle if the dimensions are 19 X 8?
54
