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The area of rectangle is : 32.0

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Q: What is the area of a rectangle of dimensions 4cm and 8?

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First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2

No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.

Come on! 88 = 11 x 8, end of story.

96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.

The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.

Related questions

It is: 4*2 = 8 square cm

First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2

Area of a rectangle = length x width If length = L and width = W, then Area = L x W For this case, the length is 4 cm longer than the width. Therefore, L = W + 4cm Replace length in the area equation at the top with this new L value: Area = (W + 4cm) x W Area = W^2 + (4cm) x W And area is 8 cm^2 (I assume you meant to say 8cm^2 is the area) Then: 8cm^2 = W^2 +4W This is a quadratic equation (because of the w^2 value), if you solve for W using the quadratic formula (Google it), you get W = 1.464cm Therefore, the length L = W + 4cm = 1.464cm + 4cm = 5.464cm Dimensions are L = 5.464cm and W = 1.464cm

12cm

The dimensions are 16 units by 8 units of mearsurement

The dimensions given are not that of a rectangle but are probably that of an isosceles trapezoid in which case it is:- Area = 0.5*(8+10)*2 = 18 square feet

No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.

Come on! 88 = 11 x 8, end of story.

96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.

54

The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.

Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.