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If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The perimeter of this rectangle is 30 inches.
Perimeter = 12 + 12 + 8 + 8 = 40.
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet
If the given dimensions are that of a rectangle then perimeter is: 34 feet
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The perimeter of a rectangle with dimensions of 8 X 6 is 28 units.To find the perimeter, you use the formula: 2l+2w, where l is the length and w is the width.In your case, the formula would read: 2(8) + 2(6) = 16 + 12 = 28
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
The perimeter of this rectangle is 30 inches.
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
Length + Width = 9, becomes 36, eg 8 + 1 becomes 32 + 4 or 5 + 4 becomes 20 + 16 New perimeter is 2 x 36 = 72 cm
The perimeter is 38.
Perimeter = 7+7+8+8 = 30 inches
Perimeter = 12 + 12 + 8 + 8 = 40.
No. For example, a 4x1 rectangle will have an area of 4 and a perimeter of 10. A 2x2 rectangle will have the same area of 4, but a perimeter of 8.