Area is found by A=Bh. B is base length,and h is height. A is area. So, to solve this problem, you would say the base length, 6 cm, and the height , 4 cm, and multiply them. 6x4=24. The are of the rectangle would have an area of 24 cm. squared.
I think it's probably 6 times 4 which is 24… I think.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
The length should be 6cm and the width is 4cm.
It does nothing.
A=1/2(b)(h). So A=1/2(6cm)(4cm). A=12cm^2, or 12 squared centimeters.
24 square centimeters
I think it's probably 6 times 4 which is 24… I think.
20cm all you have to do is add up all the sides together!
If 2 sides of the rectangle are 6cm, then the remaining 2 sides are 4cm. Area = Length x Breadth Breadth = Area / Lenghth 24 = 6 x Breadth Breadth = 24 / 6 = 4
You multiply 6 and 4.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
6 cm x 4 cm = 24cm2 (length x width = area)
12cm
The length should be 6cm and the width is 4cm.
22cm
Draw a right angled triangle with legs of 4cm and 6cm
The area of rectangle is : 18.0