If one dimension of the rectangle is 8, that means two sides have that measure. Subtracting 2 x 8 = 16 from the total perimeter of 28 leaves 28 - 16 = 12 for the other two sides, which must measure 6 each. So now we have the dimensions of length and width we need to find the area. Area = 8 x 6 = 48 square units.
Area = Length *Width = 28*4 = 112 sq cm
28 inches
The area of rectangle is : 28.0
It is: 4*7 = 28 square cm
the formular for area of a two dimesional object is: L (length) x W (width) = L x W = A Perimiter is figured out by: (L x 2) + (W x 2)= P So the area will be: 14 x 9 = 126 square feet Perimiter: (14 x 2) + (9 x 2) = 28 + 18 = 46 feet
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.
28
Area = length x width Area = 28 x 358 Area = 10,024
Area = Length *Width = 28*4 = 112 sq cm
28 inches
The area of rectangle is : 28.0
Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2
28
The area of rectangle is : 952.0
It is: 4*7 = 28 square cm
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
Assuming there is no border around the circle, then doubling the radius will give the length and width of a square (28 x 28 = 784cm2). The problem in your question is that you state it is a rectangle. Which means that the rectangle must be longer in length then width!