For a regular hexagon, half the side length can be calculated from the apothem via trigonometry:
half_side_length = apothem x tan 30°
Then:
area = apothem x 1/2 x perimeter
= apothem x 1/2 x side_length x 6
= apothem x half_side_length x 6
= 24 in x (24 in x tan 30°) x 6
≈ 1995 sq in
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
36 inches.
A regular nonagon with a side length of 9 has an apothem of 12.4 not 16. So the question is inconsistent.
The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2. Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]
It is 665.1 sq inches.
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
It is 679 square metres.
5.7735026918962... The formula for the area of a hexagon is A=.5ap, or A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
232.57 square inches.
Length of one side = 114/6 inches = 19 inches
36 inches.