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3√3/2 sq in ≈ 2.6 sq in

By joining opposite vertices of the hexagon with diagonals, the hexagon is divided up into 6 equilateral triangles, each of side 1 in

Area_hexagon = 6 x area_equilateral_triangle

= 6 x 1/2 x side x height

= 6 x 1/2 x side x (sin 60o x side)

= 6 x 1/2 x (√3/2) x side2

= 3√3/2 x side2

= 3√3/2 x (1 in)2

= 3√3/2 sq in

≈ 2.6 sq in

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Q: What is the area of a regular hexagon with each side 1 inch long?
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