Area of a rhombus= 1/2 (d₁) (d₂); where, d₁ and d₂ are the diagonals.
Solution: A=1/2 (10) (12) = 60 feet²
Area of the rhombus: 0.5*8*10 = 40 square feet
60 feet
40 sq feet
It is: 0.5*10*14 = 70 square feet
If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
40have fun cheating on your homework ha-ha
answer: 10 ft2 formula: a=1/2 x d1 x d2 d1 and d2 represent the two diagonals
It is: 0.5*8*10 = 40 square feet
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
Find the area of a rhombs with diagonals that measure 8 and 10.
It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.