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Q: What is the area of a rhombus whose diagonals are 8 and 10 feet?

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60 feet

Area = 30 sq feet

40 sq feet

60 square feet.

It is: 0.5*10*14 = 70 square feet

If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.

40have fun cheating on your homework ha-ha

The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.

It is: 0.5*8*10 = 40 square feet

answer: 10 ft2 formula: a=1/2 x d1 x d2 d1 and d2 represent the two diagonals

It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.

The diagonals of a rhombus intersect at right angles and bisect each other.... this should be the only tip you need. Good luck with your homework. how bout u be a little bit more blunt and just say the awnser?? A+:70ft^2

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