Area = 30 sq feet
the answer is 20
30
Sine = 1/sqrt(5) or 2/sqrt(5) Cosine = 2/sqrt(5) or 1/sqrt(5) Tangent = 1/2 or 2.
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
ind the area of the rhombus if AE = 20 m and DE = 32 m.
There are 20 diagonals
20 diagonals
20 diagonals
A 20 sided polygon has 170 diagonals
310
400
The area is 15*20 = 300 square feet.