the answer is 20
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.
Side length x 6 = perimeter
i think its 288
To find the perimeter of a rhombus, you need to add up the lengths of all four sides. In a rhombus, all four sides are congruent. Given that two consecutive sides are represented by 3x - 6 and x + 14, we can set up an equation: 3x - 6 = x + 14. Solving for x gives x = 10. Substituting x back into the expressions gives the side lengths as 24 and 24. Therefore, the perimeter is 4 times the length of one side, which is 4 * 24 = 96 units.
The diagonals of a rhombus intersect at 90 degrees therefore it has 4 right angle triangles with sides of 5 and 6 respectively with the hypotenuse being a side of the rhombus. So using Pythagoras' theorem: 52+62 = 61 and the square root of this is the length of each side of the rhombus which is approximately 7.81 units of measurement
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
Perimeter: 4 times square root of (3.5^2+6^2) = 2 times square root of 193 in cm
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.
The four sides of a rhombus are equal and so: 6+6+6+6 = 24
30
28
Rhombus is an equilateral four sided form. If one side is 6, the perimeter is 4 x 6 = 24. The altitude makes no difference.
If its base diagonals are 8 and 6 then by using Pythagoras it will have 4 equal lengths of 5 cm. Check: 0.5*8*6*1/3*5 = 40 cubic cm
Side length x 6 = perimeter
i think its 288
Possibly 3 by 6
To find the perimeter of a rhombus, you need to add up the lengths of all four sides. In a rhombus, all four sides are congruent. Given that two consecutive sides are represented by 3x - 6 and x + 14, we can set up an equation: 3x - 6 = x + 14. Solving for x gives x = 10. Substituting x back into the expressions gives the side lengths as 24 and 24. Therefore, the perimeter is 4 times the length of one side, which is 4 * 24 = 96 units.