First, we want to look at the base to find its area. A right triangle with a hypotenuse of 10 inches and a leg of 8 inches has its other leg at 6 inches by the Pythagorean Theorem. Now we have both legs of the right triangle, so using the formula for area of a triangle, A=bh/2, we get an area of 24 square inches.
Now, the volume of a pyramid is Bh/3, so 24*10/3=80 cubic inches.
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It depends on triangular what: pyramid, dipyramid, prism, ...
(1/3) * (base area) * height
third of base's area by heiht
Volume_any_pyramid = 1/3 × area_base × perpendicular_height For a triangular pyramid (tetrahedron) this becomes: volume = 1/6 × base_width × base_height × pyramid_height For the surface area there is no (easy) general formula: the area of the base triangle and the area of the three side triangles need to be worked out and added together.
The volume of a regular pyramid is 1/3*area of the base*hight