First, we want to look at the base to find its area. A right triangle with a hypotenuse of 10 inches and a leg of 8 inches has its other leg at 6 inches by the Pythagorean Theorem. Now we have both legs of the right triangle, so using the formula for area of a triangle, A=bh/2, we get an area of 24 square inches.
Now, the volume of a pyramid is Bh/3, so 24*10/3=80 cubic inches.
It depends on triangular what: pyramid, dipyramid, prism, ...
(1/3) * (base area) * height
third of base's area by heiht
Volume_any_pyramid = 1/3 × area_base × perpendicular_height For a triangular pyramid (tetrahedron) this becomes: volume = 1/6 × base_width × base_height × pyramid_height For the surface area there is no (easy) general formula: the area of the base triangle and the area of the three side triangles need to be worked out and added together.
v= 1/2 * length * height * width Pyramid SolidSolving for volume:
It is 36 cubic inches.
The formula for finding the volume for a triangular pyramid is half base x height x length. A triangular pyramid has four faces.
The formula to find the volume of a triangular pyramid is: 1/3 (1/2 B H ) H
It depends on triangular what: pyramid, dipyramid, prism, ...
1
The volume for any pyramid = 1/3*base area*perpendicular height
Volume = 1/3*base area*height
The height of a triangular based pyramid is given by h=2V/(bxl). V is its volume, b its base and l its length.
"triangular" is an adjective - it is not enough to define a shape. You can have a triangular pyramid or a triangular prism and there will be different methods to calculate their volumes.
(1/3) * (base area) * height
Go ask that guy
The answer will depend on what aspect the formula is for: the surface area or the volume being the most obvious options.