A square's area is side^2. The perimeter is side*4. I'll assume you meant 25 square yards. A=25 yd=s^2 s=5 yd P=5*4 yd=20 yd
It is: 18 times 12 = 216 square feet
The area is 12 sq yards to get it in feet multiply by 9 Answer = 108 sq feet
3.14159... (pi) * (r (4 yd))square The real answer is, I believe so, 50.24 yd cubed or 54.24 cubic yards.
There are 4 Sides on a Square. If each side is 2.5 yd, the Perimeter of the Square would be (4 X 2.5) or 10 yd
174 sq. yards
12 ft is 4 yd, and 18 ft is 6 yd, so we have 24 sq yds.
The perimeter of a rectangle cannot be calculated by just knowing the area unless the rectangle is a square. In which case the perimeter will be 4 x square root of the area.
The answer depend upon how to interpret "200 square yard". If it means a square with 200 yards along each side then the answer is 200 x 4 = 800 yards of fence. If it means an area of 200 sq yd, then the amount of fencing needed will depend upon the exact shape of the playground. The minimum length required would be a circle which is: length = 2 √(area × π) ≈ 50.13 yards. Any other shape would require more than this. Eg for a rectangular playground, the minimum length is when the playground is a square of side √200 giving a length of 4 × √200 ≈ 56.57 yards. Other rectangles with an area of 200 sq yds give different lengths, eg: 10 yd x 20 yd requires 60 yards 8 yd x 25 yd requires 66 yards 5 yd x 40 yd requires 90 yards 4 yd x 50 yd requires 108 yards 2 yd x 100 yd requires 204 yards 1 yd x 200 yd requires 402 yards
(12-ft x 18-ft) = (4-yd x 6-yd) = 24 square yards
if the object is a square take the square root of the area, which gives you one side length. Then multiply by 4. In this case the side length would be 15 and the perimeter would be 60.
254yd2