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9*sqrt(3)= 15.588 sq units (to 3 dp)

Q: What is the area of a triangle if all the sides are 6 units long?

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17 units in length

Yes. Heron's formula for the area of a triangle is A = √[s(s-a)(s-b)(s-c)] where a,b,c are the lengths of the sides of a triangle and s = 1/2(a+b+c). When a+b+c = 200 then s = 100. The sum of the lengths of two sides of a triangle must always exceed the length of the remaining side. The maximum area is when all three sides are of equal length, therefore the side length is 662/3 and s-a = s-b = s-c = 100 - 662/3 = 331/3. A = √[100 x (331/3)3] = 1924 sq units. The minimum area is provided by a long, narrow triangle. If an isosceles triangle is taken with the base length of 24 units and each equal side measuring 88 units then this triangle has a perimeter of 200 and an area of 1046 sq units. Provided the base length is not shortened then as the triangle 'widens' the area increases.

56 square units

The formula for the area of a triangle is (base x height)/2. Since we're dealing with a right triangle, we can say that the base and height are 10 and 11 units long, respectively. Therefore, the are is (10 x 11)/2 or 55 units squared.

55A = ab/2

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17 units in length

area = ½ × base × height = ½ × 6 units × 13 units = 39 units²

Any shape at all can have an area of 25 square units. Examples: -- A square with sides 5 units long. -- A rectangle that's 25 units long and 1 unit wide. -- A circle with diameter of 5.6419 units (rounded) -- A triangle that's 10 units high and sits on a base that's 5 units wide.

The area of a triangle is base x height ... soo...... 9 x 16 =144 cm squared =)

Yes. Heron's formula for the area of a triangle is A = √[s(s-a)(s-b)(s-c)] where a,b,c are the lengths of the sides of a triangle and s = 1/2(a+b+c). When a+b+c = 200 then s = 100. The sum of the lengths of two sides of a triangle must always exceed the length of the remaining side. The maximum area is when all three sides are of equal length, therefore the side length is 662/3 and s-a = s-b = s-c = 100 - 662/3 = 331/3. A = √[100 x (331/3)3] = 1924 sq units. The minimum area is provided by a long, narrow triangle. If an isosceles triangle is taken with the base length of 24 units and each equal side measuring 88 units then this triangle has a perimeter of 200 and an area of 1046 sq units. Provided the base length is not shortened then as the triangle 'widens' the area increases.

56 square units

The formula for the area of a triangle is (base x height)/2. Since we're dealing with a right triangle, we can say that the base and height are 10 and 11 units long, respectively. Therefore, the are is (10 x 11)/2 or 55 units squared.

55A = ab/2

27.713 square inches.

4.5 square inches

A = leg1leg2/2 = (8)(12)/2 = 48

add all of the triangle area in a pentagon to get areaThe area A of a regular polygon with n sides each s units long, perimeter p, and apothem a:A = (ans)/2 or A = (ap)/2.