Q: What is the area of an equilateral triangle with sides 8 inches long?

Write your answer...

Submit

Still have questions?

Continue Learning about Geometry

Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.

I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.

There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.

The area is 1.2 (1.16463) m2

Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches

Related questions

By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!

Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches

I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.

The area is: 15.6 (15.58846) square inches.

There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches

There is not enough information here to be able to answer this. Imagine a triangle with 2 sides, each of 10.49 inches, It would have almost no area compared with one with 3 sides of 7 inches each. Both triangles could have perimeters of 21 inches.

There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.

15.588 square inches.

The area is 1.2 (1.16463) m2

Its area is 46.8 (46.76533) square inches.