a square has 4 sides so 4 plus 4 equals 8 a triangle has 3 sides so 8 plus 3 is 11 and a circle has none so its 11
A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
If two sides of a right triangle are 13 and 11, then the third side is either sqrt(290) or 4sqrt(3). (Approx. 17.03 or 6.93)
An scalene triangle.
Yes and it will be a scalene triangle
If a triangle has equal sides, it will have equal angles of 60 degrees. It is called an equilateral triangle.
It can be but need not be.
The area of triangle is : 44.0
There is no such triangle with the given dimensions because to construct a triangle the sum of its two smaller sides must be greater than its longest side. But the area of any triangle is: 0.5*base*perpenducular height
The area of triangle is : 38.5
The area of triangle is : 82.5
The area of triangle is : 71.5
The area of triangle is : 82.5
No it is not possible because the sum of the lengths of the two sides has to be greater than the length of the third side. 5 + 4 = 9 which is less than 11, so we can't form a triangle with these sides.
Assuming these number are the coordinate pairs of a triangle then use Pythagoras to determine the lengths of the sides. Then use Hero's formula to calculate the area from the sides. Beyond that I can't be bothered to do it.
square root of 11 or 3.316625 + 5 + 6 = 14.31
A scalene triangle. It also happens to be acute.
Let's get at the idea by working backward. Suppose we know the scale factor; what will the ratio of perimeters be? For instance, suppose we have two triangles; one has sides of 3, 4, and 5 inches; the other has sides of 33, 44, and 55 inches. The scalefactor is 11: you multiply each side length of the first triangle to get the corresponding side length of the second triangle. Now look at the perimeters. The perimeter of the first triangle is 3+4+5 = 12 inches. The perimeter of the second triangle is 33+44+55 = 132 inches. The ratio of perimeters is 132/12 = 11. Do you notice that it's the same as the scale factor? This will always be true! Here is why. We can write the sides of the second triangle as 3*11, 4*11, and 5*11. Then the perimeter is 3*11 + 4*11 + 5*11 = (3 + 4 + 5)*11 using the distributive property. To find the ratio of perimeters, divide this by the perimeter of the first triangle: (3+4+5)*11 ---------- = 11 3+4+5 Let's continue and think about the ratio of areas. The triangles I chose happen to be right triangles (do you know how to show this?) so the area is half the product of the two shorter sides. Thus the area of the first triangle is (3*4)/2 = 6 square inches. The area of the second triangle is (33*44)/6 = 726 square inches. The ratio of areas is 726/6 = 121. This ratio happens to be 11 squared. It will always be true that the ratio of areas is the square of the scale factor. Again, we can see why this is true. Writing the sides of the second triangle as 3*11 and 4*11, the area is 3*11 * 4*11 = (3*4)*(11*11) Divide this by the area of the first triangle to find the ratio of areas: (3*4)*(11*11) ------------- = 11*11 = 11^2 3*4 Do you see how it works now? What is the answer to your problem?
The formula for the area of a triangle is 1/2 times the product of the triangle's base and height. Applying this formula yields and area of (6)(11)/2 = 33 square centimeters.
approx. 66 cm 3 Since an equilateral triangle has three equal side... 37 cm / 3 = 12.33 cm Area equals 1/2 * base * height one of the sides = base = 12.33cm or approx. 12Using the right triangle method to find the height... height = 12.33/2 = 6.16 * sq. root of 3 = 6.16 * 1.732 = 10.669 or approx. 11 1/2 * 12 * 11 = approx. 66 cm 3