There is no such triangle with the given dimensions because to construct a triangle the sum of its two smaller sides must be greater than its longest side.
But the area of any triangle is: 0.5*base*perpenducular height
A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
168 km². Area of rectangle = Length*Breadth = 13*7 = 91 km² Area of triangle = 1/2*Base*Height = 1/2*14*11 = 77 km² Area of figure = Area of rectangle + Area of triangle = 91+77 = 168 km²
4+7=11 7+4=11 11-4=7 11-7=4 11=4+7 11=7+4 7=11-4 4=11-7
if the angle of a triangle are in the ratio 7:11:18,find the angle
Area is 31.5 units2
The area of triangle is : 38.5
A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
The area of triangle is : 42.0
The area of triangle is : 28.0
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
168 km². Area of rectangle = Length*Breadth = 13*7 = 91 km² Area of triangle = 1/2*Base*Height = 1/2*14*11 = 77 km² Area of figure = Area of rectangle + Area of triangle = 91+77 = 168 km²
168 km². Area of rectangle = Length*Breadth = 13*7 = 91 km² Area of triangle = 1/2*Base*Height = 1/2*14*11 = 77 km² Area of figure = Area of rectangle + Area of triangle = 91+77 = 168 km²
The area of triangle is : 28.0
Area is 7 units2
4+7=11 7+4=11 11-4=7 11-7=4
The area of triangle is : 29.400000000000002
The area of triangle is : 31.5