0
What else can I help you with?
What is the area of a rectangle with a perimeter of 48 and a length of 5?
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
What is the area and perimeter of a triangle 19cm x 21 cm?
To find the area of a triangle, you need the length of the base and the height. If the triangle has a base of 19 cm and a height of 21 cm, the area would be (1/2) * base * height = (1/2) * 19 cm * 21 cm = 199.5 cm^2. To find the perimeter of a triangle, you need to add the lengths of all three sides. Without knowing the lengths of the other sides, the perimeter cannot be determined.
What is the area of a rectangle whose length is 8 cm and whose width is 19 cm?
The area of rectangle is : 152.0
What is the peremiter of a rectangle with a length of 12Cm and a height of 19Cm?
The perimeter of a rectangle is simply the sum of its four sides. In this case - 12 + 19 + 12 + 19 = 62
What is the area of the rectangle below 7 19?
It is: 7*19 = 133 square units
What is the square foot of a rectangle 19 by 35?
Area: 19*35 = 665 square feet
How do you do find the area of aparellelogram?
[Note spelling of parallel.]Orient the parallelogram so one pair of sides is horizontal & has a length b=base. These sides are separated vertically (perpendicular to the base) by a distance h=height.Then A = bh (area equals base times height).Alternatively:Given the lengths of adjacent sides (x and y) & the angle (z degrees) between them:A = x y sin(z).In the case of a rectangle, z=90 and sin(z)=1[corrected 7-19-13]
What is the perimeter of a trapezoid that is 4x4x5x6?
The perimeter of a figure is the sum of the lengths of the sides. In this case, 4 + 4 + 5 + 6 = 19
What is the area of a rectangle with a length of 14 inches and a width of 19 inches?
266 square inches
What is the area of a regular hexagon with 19 inch apothem and 12 inch sides?
Hexagon is composed of 6 equilateral triangles of side 12in, or 12 right-angled triangles, in this case with sides 6, 12 and 19. Two of these make a rectangle 6 x 19 ie 114 sqin. there are 6 such rectangles so the total area is 684 sqin. The only problem is that no such hexagon is possible, as the side must be greater than the apothem to satisfy Pythagoras?
The area of a rectangle is 247 the lenght and the width are both whole numbers greater than 1 what are the dimensions?
19 * 13
How do you draw a 47 sq cm?
Any shape with such an area will do, for example: Draw a rectangle 1 cm wide and 47 cm long; Draw a rectangle 4.7 cm wide and 10 cm long; Draw an L shape with side lengths (going clockwise from the top) 1 cm, 19 cm, 13 cm, 2 cm, 14 cm, 21 cm.
