Hexagon is composed of 6 equilateral triangles of side 12in, or 12 right-angled triangles, in this case with sides 6, 12 and 19. Two of these make a rectangle 6 x 19 ie 114 sqin. there are 6 such rectangles so the total area is 684 sqin.
The only problem is that no such hexagon is possible, as the side must be greater than the apothem to satisfy Pythagoras?
Area in square units = 0.5*(apothem)*(perimeter)
Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2. Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]
130 to find the area of any regular polygon, multiply the perimeter by one-half the apothem. This is the same as multiplying the side-lengths by the number of sides by one-half the apothem.
5.7735026918962... The formula for the area of a hexagon is A=.5ap, or A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
Assuming that you are talking about a regular hexagon, the equation is (1/2)ap, a being the apothem and pbeing the perimeter. You can also use that equation for any other regular polygon.
297 M
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
14
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
Area in square units = 0.5*(apothem)*(perimeter)
Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2. Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]
the formula to find the area of any prism is to find the area of the base (a regular hexagon, meaning that all sides and angles are the same) and multiply by the height of the prism. To find the area of a hexagon you multiply the apothem by the perimeter of the hexagon, and then divide that by 2. the apothem is a line from the center point to the center of any side, forming a right angle with a side, it doesn't matter which one. Once you find the area of the hexagon, multiply it with the height.
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
If the length measure of the sides s is given, first you have to find the length measure of the apothem a, after that use the formula of the area of a regular polygonA = (ans)/2, where n is the number of sides of the polygon, in our case this formula becomesA = 8as.