If the fountain is square, then the base covers 400 square feet of ground.
If the fountain is circular, then the base covers 314.2 square feet of ground. (rounded)
If you have a circular fountain that is 10 feet from the center to the edge, it has a radius of 10 feet. The formula for the area (A) of a circle is pi (about 3.1416) times the square of the radius (r) of the circle. For a circle with a 10-foot radius, here's the formula: Acircle = pi x r2 = 3.1416 x (10 ft)2 = 3.1416 x 100 ft2 = 314.16 ft2 = 314.16 square feet
1/3 times the area of the base times the height from the center of the base to the apex.
Split it into 7 triangles. Half-base of each is 2 so distance of centre to mid point of base is (Pythagoras) square root of (4.62 - 22) = 4.162 So area of each triangle is this times 2, and with 7 triangles multiply also by 7 to get an approximate area of 58 sq in.
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The answer depends on what sort of polygon forms the base.
the awnser is 314 sq ft.
(assuming the base is a circle) area of a circle is radius squared times Pi 10 *10*3.14 = 314 square feet. note: result is rounded.
Center of mass of hollow cone is H/3 distance above its base and that of solid cone is 3H/10 distance above its base.
If you have a circular fountain that is 10 feet from the center to the edge, it has a radius of 10 feet. The formula for the area (A) of a circle is pi (about 3.1416) times the square of the radius (r) of the circle. For a circle with a 10-foot radius, here's the formula: Acircle = pi x r2 = 3.1416 x (10 ft)2 = 3.1416 x 100 ft2 = 314.16 ft2 = 314.16 square feet
1.
base x height = Area bxh=A Height is the distance directly from base to base, not the side length.
1/3 times the area of the base times the height from the center of the base to the apex.
How far is it from 2nd base to center field? The distance from home plate to 2nd base is 127.28 feet (use pythagorean theorem z^2 = x^2 + y^2 or z = sqrt(x^2 + y^2)), so the distance from 2nd base to the fence in dead center is 277.72 feet.
Split it into 7 triangles. Half-base of each is 2 so distance of centre to mid point of base is (Pythagoras) square root of (4.62 - 22) = 4.162 So area of each triangle is this times 2, and with 7 triangles multiply also by 7 to get an approximate area of 58 sq in.
The distance between the front and rear axles is known as the "wheel base". It is measured from the center of each axle.
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The area of a parallelogram is equal to the length of the base times the shortest distance to the opposite side.