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What is the area of a triangle with a bottom length of 3 yd?
Need to know the triangle's height to tell.
What is the length of a triangle with an area of 18 square inches and a height of 12 inches?
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
What is the formula for the area for an equilateral triangle?
-- The area of any triangle is 1/2 (length of the base x height). -- For an equilateral triangle, that's equivalent to 1/2 x sqrt(3) x (length of a side).
What is the area of a triangle with a height of 5 cm and a base of 3 cm?
For a triangle, the area is equal to half the base times the height. A = 1/2*bh where A is the area of the triangle, b is the length of the base, and h is the height. In this case: * A = 1/2 * 5 * 3 = 15/2 cm2 = 7.5 cm2.
Area of equilateral triangle?
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
If a triangle has an area of forty two square inches and a base of six inches what is its height?
Formula: Area of triangle= 1/2 * base * height Therefore 42 (area of triangle) = 1/2 * 6 (base) * height 42 = 3 * height 42/3 = (3 * height)/3 14 = height Therefore, the height of triangle is 14 inches
What is the area of an equilateral triangle of side 2a?
The height of an equilateral triangle is √3/2 x side_length. So for an equilateral triangle of side length 2a, the area is: area = 1/2 x base x height 1/2 x (2a) x (√3/2 x 2a) = √3 a2
How do you find the function that models the area A of an equilateral triangle in terms of the length X of one of its sides?
The area of any triangle is (1/2) x (the base) x (the height). If the length of the side of the equilateral triangle is 'X', then its height is (X/2) x sqrt(3). Its area is then (1/2) x (X) x [ (X/2) x sqrt(3) ] = X2sqrt(3) / 4
What is the area of an equilateral triangle with sides of ten inches and height of seven inches?
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
How do you determine the area of triangles?
the formula for the area of a triangle is; a=1/2 base times height. so for example: a triangle may have a base length of 6 inches and a height of 3 inches. a=1/2 6(3) the answer would be: 9 inches.
Which is greater 3ftx2ft rectangle or a triangle with base of 3 ft height 5 fft?
The formula for the area of a rectangle is length x width; the area of a triangle is half the product of the base and the height. Thus, the rectangle has an area of 3 x 2 = 6, while the triangle has an area of (3 x 5) / 2 = 7.5. 7.5 is greater than 6, so the triangle is larger.
What is the area of the triangle in the base is 2 and the height is 3?
Since the area of a triangle is .5 x Base x Height, the area of this triangle would be: .5 x 2 x 3 = 3 So 3 units
