h=2A/b h=heightb=baseA=area
The rule for the volume of a pyramid is:V = 1/3 x Area of base x HeightSo first, we'll find the area of the base.The rule for the Area of a triangle isA = [bcSin(theta)]/2 (you can also use A = 1/2 x base x height.. but that's slower in this case)We know all that it is an equilateral triangle, and because a triangle must have 180 degrees all together, we know that each angle must be 60 degrees.So now we will find the areaA = [bcSin(theta)]/2b and c are both 7, and the angle is 60 degrees so substitute that inA = [7x7sin(60)]/2A = 21.218cm^2Now we know the Area and the Height, so we can find the volume.V = 1/3 x Area of base x HeightSubstitute in our value of 21.218cm^2 for Area and 10cm for heightV = 1/3 x 21.218 x 10V = 70.727 cm^3
Start with simplifying: 2a + -3 = 5 and reordering: -3 + 2a = 5. Then add '3' to each side of the equation: -3 + 3 + 2a = 5 + 3 and you get 2a = 8 once all like terms are combined. The last step is to divide both sides by 2 and you get the answer, which is a = 4.
It's a simple algebraic equation.If the value of 'a' is needed, it can be derived as follows:7a + 10 = 2aSubtract 2a from each side:5a + 10 = 0Subtract 10 from each side:5a = -10Divide each side by 5:a = -2
Let D represent the length of the diagonal and A the area. Suppose the sides are L and B. Then A = L*B and by Pythagoras, D2 = L2 + B2 These two equations need to be solved as simultaneous equations to get the values of L and B. One way is to use the following identities: (L + B)2 = L2 + 2LB + B2 = D2 + 2A so that L + B = sqrt(D2 + 2A) and (L - B)2 = L2 - 2LB + B2 = D2 - 2A so that L - B = sqrt(D2 - 2A) which then give 2L = sqrt(D2 + 2A) + sqrt(D2 - 2A) and 2B = sqrt(D2 + 2A) - sqrt(D2 - 2A)
The question already has the answer. If the area is 3, then you've already answered the question.If you meant the triangle had a base of 5 and a height of 3:A = base * height / 2A = 3 * 5 / 2A = 15 / 2A = 7.5
h=2A/b h=heightb=baseA=area
One side of the square, RA, is 2a cm. So the area of the square is (2a)2 = 4a2 cm2
To find the height using the formula for Area of a triangle (a = bh/2): A = bh/2 (next, multiply both sides by 2) 2A = bh (then, divide both sides by b) 2A/b = h (this is your answer)
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
Euler's line is the line that, inside of a triangle that isn't equilateral, contains the orthocenter, the circumcenter, the centroid, and the center of the nine-point circle
If A = (b x h) ÷ 2, then h = 2A ÷ b, where A is the area of a triangle, b is the length of its base, and h is its height.
Area of a square = A = 2S, 1/2A = S A = 4, 1/2A = 2 S = 2 Each side is 2 m long
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
Well for a triangle A= (1/2)•B•H I'm assuming they gave you the base measurement. So you want to get H alone. You'd first move the (1/2) by manipulating the equation. Multiply each side by 2. So 2A=B•H. Then, you manipulate the equation further to get H alone so that you can find the height. Divide each side by B. So (2A)/B = H.
2a = 8 + 4aSubtract 8 from each side:2a - 8 = 4aSubtract 2a from each side:-8 = 2aDivide each side by 2:-4 = a
2a + 21 = 8a - 9Add 9 to each side:2a + 30 = 8aSubtract 2a from each side:30 = 6aDivide each side by 6:5 = a