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What is the axis of symmetry of the quadratic function y 2(x 3)2 5?
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What is the axis of symmetry for the function - y equals x squared plus 2x plus 1?
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
How do you find the equation of the axis of symmetry of y equals 2x plus 2 plus 4x plus 2?
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
What is the axis of symmetry of -3x2 plus 2x minus 3?
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
What is the axis of symmetry of x2 plus 2x plus 6?
That will be a vertical line that passes through the parabola at the point where it's slope is equal to zero. The first step then, is to take the derivative of the curve with respect to x: y = x2 + 2x + 6 dy/dx = 2x + 2 Then let dy/dx equal zero, and solve for x: 0 = 2x + 2 2x = -2 x = -1 So the axis of symmetry is the line x = -1.
What is a equation with one or more variables called?
This depends on the type of equation. Example: y=2x +2 is called a linear function. in the form of a binomial. y= 2x^2 +3x +2 =is a quadratic function. in the form of a trinomial.
What is the axis of symmetry for the function - y equals x squared plus 2x plus 1?
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
How do you find the equation of the axis of symmetry of y equals 2x plus 2 plus 4x plus 2?
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
What is the vertex and the axis of symmetry for the function y equals x2 plus 4x plus 1?
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
What is the axis of symmetry of x2 plus 2x-3?
It is at: (-1, 0)
What is the equation of the axis of symmetry and the vertex of the graph gx-2x-12x 6?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
What is the axis of symmetry of -3x2 plus 2x minus 3?
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
What is the axis of symmetry of x2 plus 2x plus 6?
That will be a vertical line that passes through the parabola at the point where it's slope is equal to zero. The first step then, is to take the derivative of the curve with respect to x: y = x2 + 2x + 6 dy/dx = 2x + 2 Then let dy/dx equal zero, and solve for x: 0 = 2x + 2 2x = -2 x = -1 So the axis of symmetry is the line x = -1.
How do you find the quadratic function of y equals 7x2 plus 2x plus 11?
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
What is a equation with one or more variables called?
This depends on the type of equation. Example: y=2x +2 is called a linear function. in the form of a binomial. y= 2x^2 +3x +2 =is a quadratic function. in the form of a trinomial.
What happens if there are no zeros in a quadratic function?
Whether or not a function has zeros depends on the domain over which it is defined.For example, the linear equation 2x = 3 has no zeros if the domain is the set of integers (whole numbers) but if you allow rational numbers then x = 1.5 is a zero.A quadratic function such as x^2 = 2 has no rational zeros, but it does have irrational zeros which are sqrt(2) and -sqrt(2).Similarly, a quadratic equation need not have real zeros. It will have zeros if the domain is extended to the complex field.In the coordinate plane, a quadratic without zeros will either be wholly above the horizontal axis or wholly below it.
What is y equals 2x2 plus 5x-3?
It is the equation of a quadratic function that happens to factor very nicely: y = 2x2 + 5x - 3 = (x + 3)(2x - 1). When the product of two numbers equals zero, then one or other of them must equal zero. Therefore, when y = 0, one of the two factors must also equal zero: Hence, either x = -3 or x = ½, when y = 0. This implies that the graph of this function crosses the x-axis at two places: namely, at (0,-3) and at (0,½). As the graph of every quadratic function is a parabola, its axis of symmetry is the vertical line passing through the point on the x-axis that is mid-way betwixt the two points named above, where the function crosses the x-axis: namely, at (0,-1¼). To find the vertex of the above parabola, we solve for y where x = -1¼: y = (x + 3)(2x - 1) = (-1¼ + 3)(-1¼ - 1) = (1¾)(-2¼) = (7/4)(-9/4) = 63/16 = 3 15/16 -3; hence, the vertex is located at the point, (-1¼,315/16).
