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y = 2x² + 4x - 10

The axis of symmetry can be found by setting the derivative equal to zero:

y = ax² + bx + c

y' = 2ax + b = 0

x = -b/2a

Or you could just memorize the formula above.

x = -b/2a

x = -4 / (2*2)

x = -1.

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Q: What is the axis symmetry of the equation y equals 2x² 4x - 10?
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