The center of mass of a triangle is better known as the centroid - the intersection of the medians. One median of the triangle with coordinates A(0,-12), B(0,12) and C(1,0) is obvious: the middle of side AB is (0,0) so the line from C to that middle is the x-axis. Another media goes from A to the midpoint of BC. This midpoint M can be expressed as (1/2,6). We want to know the equation of line AM: it's x-intercept, at A, is -12; it goes up 18 units over a horizontal distance of 1/2 a unit, so its slope is 18*2=36. Thus, the equation is y=36x-12. We now solve for the intersection of the two medians: y=0 and y=36x-12. This gives us 36x-12=0 or x=12/36=1/3, so the intersection point is (1/3,0). Theoretically, we could try to find the equation of the third median, but there is no need - we know that it has to pass through the intersection of the first two. So the coordinates of the centroid, or the center of mass, are just this intersection: the point (1/3,0). The coordinates of the center of mass, or centroid, are just the average of the coordinates of the corners. This is a much faster way of calculating the centroid. Our three points are (0,12), (0,-12), and (1,0). The mean of the x-coordinates is (0+0+1)/3 or 1/3. The mean of the y-coordinates is (12-12+0)/3 or 0. So the centroid's coordinates are (1/3,0).
Not too sure of the question but if A is (1, 2) and B is (-3, -1) then it is a right angle triangle if the coordinates of C are at (1, -1) or (-3, 2)
If the original point was (-4, 12) then the image is (-16, 48).
A radius of a regular triangle is 12 . find the length of one side of the triangle?
You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.
An obtuse triangle.
The coordinates are the vertices of a triangle since they form three points.
Not too sure of the question but if A is (1, 2) and B is (-3, -1) then it is a right angle triangle if the coordinates of C are at (1, -1) or (-3, 2)
If the original point was (-4, 12) then the image is (-16, 48).
they are 12 83
A radius of a regular triangle is 12 . find the length of one side of the triangle?
If you mean vertices of: (-1, -1) (-1, 3) and (5, -1) then when plotted on the Cartesian plane it will form a right angle triangle with a base of 6 units and a height of 4 units. Area of triangle: 0.5*6*4 = 12 square units
Coordinates: 26°12′16″S 28°2′44″E
The coordinates are (10, 5).
You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.
An obtuse triangle.
that's not a triangle
The area of triangle is : 12.0