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What is the centre and radius of a circle embeded on the Cartesian plane whose equation is x squared plus y squared -4x -2y -4 equals 0 showing key aspects of work?
Wiki User
∙ 11y ago
Note that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circle's centre
Equation: x2+y2-4x-2y-4 = 0
Completing the squares: (x-2)2+(y-1)2 = 9
Therefore: centre = (2, 1) and radius = 3
Wiki User
∙ 11y ago
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