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What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Wiki User
∙ 8y ago
Points: (2, 3) and (11, 13)
Slope: 10/9
Equation: 9y = 10x+7
Wiki User
∙ 8y ago
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What is the length of the line and its equation including its perpendicular bisector equation that spans the points of 2 3 and 5 7 on the Cartesian plane showing key stages of work?
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
What is the equation for the line passing through the points of 2 2 and 4 -3 on the Cartesian plane?
It is: y = -2.5x+7
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?
The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16
What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
What is the equation of the line whose end points are 5 2 and 3 2 on the Cartesian plane?
The equation is y = 2
What is the length of the line and its equation including its perpendicular bisector equation that spans the points of 2 3 and 5 7 on the Cartesian plane showing key stages of work?
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
What is the perpendicular bisector equation of the line segment whose end points are at -2 4 and -4 8 on the Cartesian plane?
End points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 Perpendicular bisector equation: y -6 = 1/2(x--3) => y = 0.5x+7.5
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
What is the equation for the line passing through the points of 2 2 and 4 -3 on the Cartesian plane?
It is: y = -2.5x+7
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?
The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16
What is the equation of the line that connects the points 0 1 to 1 0 and its distance on the Cartesian plane?
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
What are coordinates for -4x plus 9y equals 0?
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
What is the answer for this question in the Cartesian plane (54)(63)?
If you mean points of (5, 4) and (6, 3) then the slope is -1 and equation is y=-x+9
What is used to locate points x y in the coordinate plane?
It is the straight line equation that can be used to locate coordinates of x and y on the Cartesian plane
What type of graph does an equation of the form x equals a where a is any real number have and why?
It is a horizontal line in the Cartesian plane, or a vertical line in the complex plane. The reason is that these points satisfy the equation while no others do.
