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Q: What is the complete factorization of the trinomial 3x2 10x - 8?

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Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored

-(3x - 4)(x - 2)

-(3x+4)(x+2)

-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)

It is: (-3x-4)(x+2) when factored

3x2 + 10x + 3 = (x + 3)(3x + 1).

3x2 + 36x + 81 = 3(x2 + 13x + 27)

3x2 - 10x - 8 = (3x + 2) (x - 4)

the answer is 60

If you mean: 27x2-90x+27 then divide all terms by 9 which is then 3x2-10x+3 And when factored it is: (3x-1)(x-3)

16

[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .

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